Details Page for 0.1602

Complete Solution is Known:

MSV File: q-0.1602.msv

Growth Pattern:

(Click on a heap to see details)

Details for Q₁₅(0.1602):

Q = <a,b,c,d,e,f,g | a²=1, b⁴=b², bc³=b³c, c⁴=b²c², b²d=b³, bcd²=bc, c²d²=c², bd³=bd, cd³=cd, d⁴=d², b²e=e, ce=ab²c, de=be, e²=b²c², b²f=b²c, bcf=bc², c²f=c³, ef=ab²c, bdf³=b²c, cdf³=b³c², d²f³=cd²f², f⁴=b²c², b²g=b², bcg=bc, c²g=c², d²g=g, eg=e, f²g=b²c², g²=g>

P = {a, b², c², b²c², ad, bcd, ac³d, ad², ad³, be, bf, bd²f, f², acdf², d²f², bf³, ag, adg, cfg}

Phi = 1 a 1 1 a b b a c 1 a c d e f g

Monoid Structure