Details Page for 0.1367

Complete Solution is Known:

MSV File: q-0.1367.msv

Growth Pattern:

(Click on a heap to see details)

Details for Q₇₁(0.1367):

Q = <a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t | a²=1, b³=b, c³=c, bd=bc, c²d=d, d²=b²c², bce=abc, de²=ade, e³=ae², bf=bc, c²f=f, def=cde, e²f=ce², f²=c²e², bg=abc, eg=ade, dfg=ab²c, g²=b²c², bch=abc, eh=acde, c²gh=gh, dgh=adfh, fgh=b²c², h²=b²c², bi=bh, ci=dh, di=ab²c, ei=b²c², fi=cdfh, gi=acdfh, hi=b²c², i²=b²c², bj=bc, c²ej=ej, fj=ce²j, dgj=ab²c, c²hj=hj, dhj=dfh, ghj=b²c², ij=cdfh, j²=b²c², bk=abc, c²k=k, dk=dg, ek=ade, fk=cde, gk=b²c², hk=gh, ik=acdfh, jk=dej, k²=b²c², b²l=l, cl=bc, dl=bc, e²l=ael, fl=bc, gl=abc, hl=abc², il=abc², jl=bc, kl=abc, l²=b²c², em=ac²m, fm=cm, gm=adm, hm=acdm, im=ab²c²m, c²jm=jm, km=adm, lm=bc²m, m²=b²c², n=b²m, bo=abc²m, c²eo=eo, e²o=aeo, fo=aceo, go=deo, c²ho=ho, dho=b²cm, io=b²c²m, c²jo=jo, ejo=ajo, hjo=acdjo, ko=deo, lo=abc²m, o²=b²c², p=o, bcq=abc, eq=ac²q, fq=cq, gq=adq, hq=acdq, iq=b²c², c²jq=jq, kq=adq, lq=abc², bmq=abc²m, c²mq=mq, c²oq=oq, q²=b²c², bcr=b²c²m, er=ac²r, fr=cr, gr=adr, hr=acdr, ir=abcm, c²jr=jr, kr=adr, lr=b²cm, mr=bc, or=abc, qr=abcm, r²=b²c², s=b²c²m, bt=abc, ct=ab²c², dt=ab²c², et=b²c, ft=ab²c², gt=b²c², ht=b²c, it=b²c, jt=ab²c², kt=b²c², lt=abc, qt=b²c, rt=abc²m, t²=b²c²>

P = {a, b², ac, ac², b²c², acd, abe, acde, e², b²e², c²e², af, acf, adf, cg, dg, abh, acj, ac²j, adj, adej, ce²j, agj, ck, bel, abm, aco, ac²o, ado, ho, amo, ac²mo, acdmo, acjmo, adjmo, cq, jq, coq, joq, acmoq, ajmoq, ar, ab²r, ac²r, acdr, acjr, adjr, at, mot}

Phi = 1 a a 1 bc bc abc abc b b a ab²c² c d bc bc abc bc² bc² e ab²e² f ade g abc abc bc² bc h i j b²c k fh bq l bc m b²m o o b²c bcm bq bq bc bc² b²m ab²c ab²c b²c q ab²c² r bc² bc² abc abc ab²c b²c q ab²c² r bc² bc bc abc b²c²m b²c q ab²c² t bcm bc bc abc b²c²m b²c²m b²cm

Monoid Structure